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	<title>Comments on: Mixture of helium and oxygen are used in scuba diving.?</title>
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		<title>By: Steve O</title>
		<link>http://www.diveblueplanet.com/scuba-diving-tanks/mixture-of-helium-and-oxygen-are-used-in-scuba-diving/comment-page-1#comment-849</link>
		<dc:creator>Steve O</dc:creator>
		<pubDate>Mon, 04 Jan 2010 02:40:59 +0000</pubDate>
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		<description>find moles, using molar masses:
1.96 g He @ 4.00 g/mole = 0.49 moles Helium

60.8 g O2 @ 32.0 g/mol = 1.90 moles  oxygen

total moles = 2.39 moles
===========================

A) the mole fractions of two gases?

Helium:
0.49 moles Helium / 2.39 total moles = 0.205 helium&#039;s mole fraction

1.90 mole O2 / 2.39  total moles = 0.795 oxygen&#039;s mole fraction
=================================

B) their partial pressures?

first find total pressure:
PV=nRT
P(5.00L) = 2.39 moles (0.08206 Litre-atm / mol-K)(298K)
total pressure = 11.69 atm

B) their partial pressures?
Helium:
11.69 (0.205 helium&#039;s mole fraction) = 2.396 atm Helium
your answer(3sigfigs): 2.40 atm Helium partial pressure

Oxygen:
11.69 - 2.40 = 9.29 atm oxygen
your answer is: 9.29 atm Oxygen partial pressure
===============================
C) total pressure?

your answer(3sigfigs): 11.7 atm&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;</description>
		<content:encoded><![CDATA[<p>find moles, using molar masses:<br />
1.96 g He @ 4.00 g/mole = 0.49 moles Helium</p>
<p>60.8 g O2 @ 32.0 g/mol = 1.90 moles  oxygen</p>
<p>total moles = 2.39 moles<br />
===========================</p>
<p>A) the mole fractions of two gases?</p>
<p>Helium:<br />
0.49 moles Helium / 2.39 total moles = 0.205 helium&#8217;s mole fraction</p>
<p>1.90 mole O2 / 2.39  total moles = 0.795 oxygen&#8217;s mole fraction<br />
=================================</p>
<p>B) their partial pressures?</p>
<p>first find total pressure:<br />
PV=nRT<br />
P(5.00L) = 2.39 moles (0.08206 Litre-atm / mol-K)(298K)<br />
total pressure = 11.69 atm</p>
<p>B) their partial pressures?<br />
Helium:<br />
11.69 (0.205 helium&#8217;s mole fraction) = 2.396 atm Helium<br />
your answer(3sigfigs): 2.40 atm Helium partial pressure</p>
<p>Oxygen:<br />
11.69 &#8211; 2.40 = 9.29 atm oxygen<br />
your answer is: 9.29 atm Oxygen partial pressure<br />
===============================<br />
C) total pressure?</p>
<p>your answer(3sigfigs): 11.7 atm<br /><b>References : </b></p>
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